Solved

The Integral $\int \sqrt { 9 - 16 x ^ { 2 } } d x$

Question 5

Multiple Choice

The integral $\int \sqrt { 9 - 16 x ^ { 2 } } d x$ is

A) $- \frac { 9 \sin ^ { - 1 } \left( \frac { 4 x } { 3 } \right) + 4 x \sqrt { 9 - 16 x ^ { 2 } } } { 8 } + C$
B) $\frac { 9 \sin ^ { - 1 } \left( \frac { 4 x } { 3 } \right) + 4 x \sqrt { 9 - 16 x ^ { 2 } } } { 8 } + C$ .
C) $\frac { 9 \sin ^ { - 1 } \left( \frac { 4 x } { 3 } \right) + x \sqrt { 9 - 16 x ^ { 2 } } } { 8 } + C$
D) $\frac { 9 \sin ^ { - 1 } \left( \frac { 4 x } { 3 } \right) - 4 x \sqrt { 9 - 16 x ^ { 2 } } } { 8 } + C$
E) $- \frac { 9 \sin ^ { - 1 } \left( \frac { 4 x } { 3 } \right) + 4 x \sqrt { 9 - 16 x ^ { 2 } } } { 8 } + C$ .

The Integral ∫9−16x2dx\int \sqrt { 9 - 16 x ^ { 2 } } d x∫9−16x2​dx

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeSign up to view answer

The Integral $\int \sqrt { 9 - 16 x ^ { 2 } } d x$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge