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Let f(x)=12x33x2+6x4f ( x ) = \frac { 1 } { 2 } x ^ { 3 } - 3 x ^ { 2 } + 6 x - 4

Question 124

Multiple Choice

Let f(x) =12x33x2+6x4f ( x ) = \frac { 1 } { 2 } x ^ { 3 } - 3 x ^ { 2 } + 6 x - 4 on [1,3][ 1,3 ] The absolute minimum and maximum of ƒ are located respectively at x =


A) 1,3
B) 3,1
C) 1,2
D) 2,3
E) 3,2

Correct Answer:

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