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Let r(t)=cos(2t)isin(2t)j+4tk\mathbf { r } ( t ) = \cos ( 2 t ) \mathbf { i } - \sin ( 2 t ) \mathbf { j } + 4 t \mathbf { k }

Question 12

Multiple Choice

Let r(t) =cos(2t) isin(2t) j+4tk\mathbf { r } ( t ) = \cos ( 2 t ) \mathbf { i } - \sin ( 2 t ) \mathbf { j } + 4 t \mathbf { k } Then the unit tangent vector T(π4) \mathbf { T } \left( \frac { \pi } { 4 } \right) is


A) 15i+25k- \frac { 1 } { \sqrt { 5 } } \mathbf { i } + \frac { 2 } { \sqrt { 5 } } \mathbf { k }
B) 15i+25k\frac { 1 } { \sqrt { 5 } } \mathbf { i } + \frac { 2 } { \sqrt { 5 } } \mathbf { k }
C) 15i25k- \frac { 1 } { \sqrt { 5 } } \mathbf { i } - \frac { 2 } { \sqrt { 5 } } \mathbf { k }
D) 15i25k\frac { 1 } { \sqrt { 5 } } \mathbf { i } - \frac { 2 } { \sqrt { 5 } } \mathbf { k }
E) 25i+15k- \frac { 2 } { \sqrt { 5 } } \mathbf { i } + \frac { 1 } { \sqrt { 5 } } \mathbf { k }

Correct Answer:

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