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The Center and Radius of the Sphere 3x2+3y2+3z2+6xz3=03 x ^ { 2 } + 3 y ^ { 2 } + 3 z ^ { 2 } + 6 x - z - 3 = 0

Question 20

Multiple Choice

The center and radius of the sphere 3x2+3y2+3z2+6xz3=03 x ^ { 2 } + 3 y ^ { 2 } + 3 z ^ { 2 } + 6 x - z - 3 = 0 are


A) (1,0,16) ;2\left( - 1,0 , - \frac { 1 } { 6 } \right) ; 2
B) (1,0,16) ;7\left( - 1,0 , \frac { 1 } { 6 } \right) ; 7
C) (1,0,6) ;5( - 1,0 , - 6 ) ; 5
D) (1,0,16) ;736\left( - 1,0 , \frac { 1 } { 6 } \right) ; \frac { \sqrt { 73 } } { 6 }
E) (1,0,16) ;13\left( 1,0 , \frac { 1 } { 6 } \right) ; \sqrt { 13 }

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