A Random Sample of 9 Scores Is Collected with a Sample

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The Answer is Degrees of freedom (v) are equal to _n_-_{1, thus 9}_{- 1}_{= 8}_{.
The hypothesized populati}_{on variance is provided to us (15}_{). Plugging these values into the formula, we find the test statistic value:}

x^{2}=\frac{v s^{2}}{\sigma_{0}^{2}}=\frac{8(16)}{15}=8.53

_{From Appendix Table 3, and using an alpha level of .05}_{(i.e., tabled values listed under .975 and .025)}_{and degrees of freedom (}_v_{) of}₈_{, we determine the critical values to be}_2.17973_and_17.5345_{. As t}_{he test}_{statistic (8.53}₎_does_{not exceed}_{one of the critic}_al_values_{, our decision is to}_{fail to}_{reject the null hypothesis.}

A Random Sample of 9 Scores Is Collected with a Sample

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A Random Sample of 9 Scores Is Collected with a Sample

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Correct Answer:
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