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Using ΔfG298\Delta _{f}G_{298}^{\circ} Data Given Below Calculate the Standard Gibbs Energy Change

Question 14

Multiple Choice

Using ΔfG298\Delta _{f}G_{298}^{\circ} data given below:
C12H22O11( s) O2( g) CO2( g) H2O(l) ΔfG298/kJmol115430394.4237.1\begin{array}{|c|c|c|c|c|}\hline & \mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(\mathrm{~s}) & \mathrm{O}_{2}(\mathrm{~g}) & \mathrm{CO}_{2}(\mathrm{~g}) & \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \\\hline \Delta_{\mathrm{f}} G_{298}^{\circ} / \mathrm{kJ} \mathrm{mol}^{-1} & -1543 & 0 & -394.4 & -237.1 \\\hline\end{array}
Calculate the standard Gibbs energy change, ΔTG298\Delta _{T}G_{298}^{\circ} (kJ mol-1) , for the following reaction:
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)


A) + 911.5.
B) - 5797.9.
C) + 5797.9.
D) - 911.5.

Correct Answer:

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