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One of Nature's Patterns Connects the Percent of Adult Birds

Question 8

Multiple Choice

One of nature's patterns connects the percent of adult birds in a colony that return from the previous year and the number of new adults that join the colony. Here are data for 13 colonies of sparrowhawks (a type of bird) and the software output:
?
?
 Percent return 74668152736252456246604638 New adults 56811121516171818192020\begin{array} { | l | l | l | l | l | l | l | l | l | l | l | l | l | l | } \hline \text { Percent return } & 74 & 66 & 81 & 52 & 73 & 62 & 52 & 45 & 62 & 46 & 60 & 46 & 38 \\\hline \text { New adults } & 5 & 6 & 8 & 11 & 12 & 15 & 16 & 17 & 18 & 18 & 19 & 20 & 20 \\\hline\end{array} ?
Simple linear regression results:
Dependent Variable: New adults
Independent Variable: percentage return
New adults =31.9342590.30402295= 31.934259 - 0.30402295 percentage return
Sample size: 13
RR (correlation coefficient ) =0.7484673) = - 0.7484673
Rsq=0.5602033\mathrm { R } - \mathrm { sq } = 0.5602033
Estimate of error standard deviation: 3.66689133.6668913

Parameter estimates:

 Parameter  Estimate  Std. Err.  Alternative  DF  T-Stat  p-value  Intercept 31.9342594.83761640116.6012383<0.0001 Slope 0.304022950.0812200340113.74320140.0032\begin{array}{|l|r|r|r|r|r|r|}\hline \text { Parameter } & \text { Estimate } & \text { Std. Err. } & \text { Alternative } & \text { DF } & \text { T-Stat } & \text { p-value } \\\hline \text { Intercept } & 31.934259 & 4.8376164 & \neq 0 & 11 & 6.6012383 & <0.0001 \\\hline \text { Slope } & -0.30402295 & 0.081220034 & \neq 0 & 11 & -3.7432014 & 0.0032 \\\hline\end{array} A scatterplot of the data shows that there is a linear relationship between the percent x of adult sparrowhawks that return to a colony from the previous year and the number y of new adult birds that join the colony.
What is the least-squares regression line for predicting y from x


A) ? = 31.934 - 0.304x
B)
? = -0.304 + 31.934x
C) ? = -31.934 + 0.304x
D) ? = 0.304 - 31.934x

Correct Answer:

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