Assuming That Both Parents Are Heterozygous for a Recessive Gene $4 \left( \frac { 1 } { 4 } \right) ^ { 3 } \left( \frac { 3 } { 4 } \right) ^ { 1 }$

Multiple Choice

Assuming that both parents are heterozygous for a recessive gene, the probability that a single offspring develops the recessive trait is 1/4. Assuming separate births are independent, the probability that exactly three out of four offspring develop the trait is given by

A) $4 \left( \frac { 1 } { 4 } \right) ^ { 3 } \left( \frac { 3 } { 4 } \right) ^ { 1 }$
B) $\left( \frac { 1 } { 4 } \right) ^ { 3 } \left( \frac { 3 } { 4 } \right) ^ { 1 }$
C) $4 \left( \frac { 1 } { 4 } \right) ^ { 1 } \left( \frac { 3 } { 4 } \right) ^ { 3 }$
D) $\left( \frac { 1 } { 4 } \right) ^ { 1 } \left( \frac { 3 } { 4 } \right) ^ { 3 }$