Essay
import java.nio.file.*;
import java.io.*;
import java.nio.channels.FileChannel;
import java.nio.ByteBuffer;
import static java.nio.file.StandardOpenOption.*;
import java.util.Scanner;
public class CreateEmployeesRandomFile
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
Path file =
Paths.get("C: \\Java\\Chapter.13\\RandomEmployees.txt");
String s = "000, ,00.00" +
System.getProperty("line.separator");
final int RECSIZE = s.length();
FileChannel fc = null;
String delimiter = ",";
String idString;
int id;
String name;
String payRate;
final String QUIT = "999";
try
{
fc = (FileChannel)Files.newByteChannel(file, READ, WRITE);
System.out.print("Enter employee ID number >> ");
idString = input.nextLine();
while(!(idString.equals(QUIT)))
{
_____________________________
System.out.print("Enter name for employee #" +
id + " >> ");
name = input.nextLine();
System.out.print("Enter pay rate >> ");
payRate = input.nextLine();
s = idString + delimiter + name + delimiter +
payRate + System.getProperty("line.separator");
byte[] data = s.getBytes();
ByteBuffer buffer = ByteBuffer.wrap(data);
_____________________________
fc.write(buffer);
System.out.print("Enter next ID number or " +
QUIT + " to quit >> ");
idString = input.nextLine();
}
fc.close();
}
catch (Exception e)
{
System.out.println("Error message: " + e);
}
The above program will accept any number of employee records as user input and write the records to a file in a loop. In the first shaded line, create the statement to accept the employee data value from the keyboard as a String and convert it to an integer using the parseInt() method. In the second shaded line, create the statement to compute the record's desired position by multiplying the ID number value by the record size.
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