Let X Be a Continuous Random Variable with Probability Density$$f ( x ) = \left\{ \begin{array} { l l }
\frac { x ^ { 3 } } { 4 } & 0 \leq x \leq 2 \
0 & \text { else }
\end{array} \right.$$

Question

Let X Be a Continuous Random Variable with Probability Density$$f ( x ) = \left\{ \begin{array} { l l } 
\frac { x ^ { 3 } } { 4 } & 0 \leq x \leq 2 \
0 & \text { else }
\end{array} \right.$$

Examlex · Accepted Answer

The Answer is

f ( x ) = \left\{ \begin{array} { l l } \frac { ( \ln ( x ) ) ^ { 3 } } { 64 x } & 1 < x < e ^ { 4 } \0 & ext { else. }\end{array} ight.

Let X Be a Continuous Random Variable with Probability Density $f ( x ) = \left\{ \begin{array} { l l } \frac { x ^ { 3 } } { 4 } & 0 \leq x \leq 2 \\0 & \text { else }\end{array} \right.$

Short Answer

Correct Answer:
Verified

Let X Be a Continuous Random Variable with Probability Density f(x)={x340≤x≤20 else f ( x ) = \left\{ \begin{array} { l l } \frac { x ^ { 3 } } { 4 } & 0 \leq x \leq 2 \\0 & \text { else }\end{array} \right.f(x)={4x3​0​0≤x≤2 else ​

Short Answer

Correct Answer:VerifiedShow Answer

Let X Be a Continuous Random Variable with Probability Density $f ( x ) = \left\{ \begin{array} { l l } \frac { x ^ { 3 } } { 4 } & 0 \leq x \leq 2 \\0 & \text { else }\end{array} \right.$

Correct Answer:
Verified