The Random Variable X, Y and Z Have Joint Probability

Short Answer

The random variable X, Y and Z have joint probability density function $$f ( x , y , z ) = \left\{ \begin{array} { l l } \frac { \left( x ^ { 2 } + y ^ { 2 } + z ^ { 2 } \right) } { K } & 0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1 \\0 & \text { else }\end{array} \right.$$
(a) Find K.
(b) Find P(X>.2|Y+Z>1).