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Σ(XiXˉ)(YiYˉ)=ΣYiXiYˉΣXi\Sigma \left( X _ { i } - \bar { X } \right) \left( Y _ { i } - \bar { Y } \right) = \Sigma Y _ { i } X _ { i } - \bar { Y } \Sigma X _ { i }

Question 6

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Σ(XiXˉ)(YiYˉ)=ΣYiXiYˉΣXi\Sigma \left( X _ { i } - \bar { X } \right) \left( Y _ { i } - \bar { Y } \right) = \Sigma Y _ { i } X _ { i } - \bar { Y } \Sigma X _ { i }

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