You Rejected the Null Hypothesis for the Following Cases (2

Question

Examlex · Accepted Answer

The Answer is a. The appropriate test of association is phi

\phi = \sqrt { \frac { \chi ^ { 2 } } { n } }

b.

\begin{array} { l } ext { i. } \chi ^ { 2 } = 4.235 ; n = 153 ext {. } \\phi = \sqrt { \frac { 4.235 } { 153 } } = 0.17 \\end{array}

17% of the variance within the DV variable is explained by the IV, leaving 83% of the variance unexplained (explained by other variables).

\begin{array} { l } ext { ii. } \chi ^ { 2 } = 18.567 ; n = 215 \- \phi = \sqrt { \frac { 18.567 } { 215 } } = 0.29\end{array}

29% of the variance within the DV variable is explained by the IV, leaving 71% of the variance unexplained (explained by other variables).
iii.

\begin{array} { l } \chi ^ { 2 } = 3.898 ; n = 310 \\phi = \sqrt { \frac { 3.898 } { 310 } } = 0.11\end{array}

11% of the variance within the DV variable is explained by the IV, leaving 89% of the variance unexplained (explained by other variables).
iv.

\quad \chi ^ { 2 } = 22.33 ; n = 146

.

\phi = \sqrt { \frac { 22.33 } { 146 } } = 0.39

39% of the variance within the DV variable is explained by the IV, leaving 61% of the variance unexplained (explained by other variables).
v. χ² = 10.659; n = 189.

\phi = \sqrt { \frac { 10.659 } { 189 } } = 0.24

24% of the variance within the DV variable is explained by the IV, leaving 76% of the variance unexplained (explained by other variables).

\begin{array} { l } ext { i. } \chi ^ { 2 } = 29.66 ; n = 195 ext {. } \\phi = \sqrt { \frac { 29.66 } { 195 } } = 0.39\end{array}

vi.
39% of the variance within the DV variable is explained by the IV, leaving 61% of the variance unexplained (explained by other variables).

You Rejected the Null Hypothesis for the Following Cases (2

Essay

Correct Answer:
Verified

You Rejected the Null Hypothesis for the Following Cases (2

Essay

Correct Answer:VerifiedShow Answer

Correct Answer:
Verified