The Following Is a Distribution Representing the Number of Prior

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ext { Range } = 13 ext { (highest } ) - 0 ( ext { lowest } ) = 13

ext { Variance } = \frac { \Sigma ( x - x ) ^ { 2 } } { n - 1 } = \frac { 407.54 } { 25 } = 16.30

Standard deviation

( s ) = \sqrt { \frac { \Sigma ( x - x ) ^ { 2 } } { n - 1 } } = \sqrt { \frac { 407.54 } { 25 } } = 4.04

The average number of prior convictions an individual had was 4.69

( \bar { \chi } )

. The standard deviation was 4.4, meaning that the majority of inmates had between 0.65 and 8.73 prior convictions.
$ext { Range } = 13 ext { (highest } ) - 0 ( ext { lowest } ) = 13 ext { Variance } = \frac { \Sigma ( x - x ) ^ { 2 } } { n - 1 } = \frac { 407.54 } { 25 } = 16.30 Standard deviation ( s ) = \sqrt { \frac { \Sigma ( x - x ) ^ { 2 } } { n - 1 } } = \sqrt { \frac { 407.54 } { 25 } } = 4.04 The average number of prior convictions an individual had was 4.69 ( \bar { \chi } ) . The standard deviation was 4.4, meaning that the majority of inmates had between 0.65 and 8.73 prior convictions.$

The Following Is a Distribution Representing the Number of Prior

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The Following Is a Distribution Representing the Number of Prior

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Correct Answer:
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