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    Exam 13: Parallel Communication and Runtime Analysis
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    The Time Taken by All-To- All Broadcast on a Mesh
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The Time Taken by All-To- All Broadcast on a Mesh

Question 15

Question 15

Multiple Choice

The time taken by all-to- all broadcast on a mesh is .


A) t= (ts + twm) (p-1)
B) t= ts logp + twm(p-1)
C) t= 2ts(?p - 1) - twm(p-1)
D) t= 2ts(?p - 1) + twm(p-1)

Correct Answer:

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