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Find the Absolute Maximum and Minimum Of f(x)=x48x2+12f ( x ) = x ^ { 4 } - 8 x ^ { 2 } + 12

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Find the absolute maximum and minimum of f(x)=x48x2+12f ( x ) = x ^ { 4 } - 8 x ^ { 2 } + 12 on the interval -1 \le x \le 2.

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