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Determine the Absolute Maximum and Minimum Of f(x)=x42x2+5f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 5

Question 126

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Determine the absolute maximum and minimum of f(x)=x42x2+5f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 5 on the interval -2 \le x \le 1.

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Maximum is 13 at x =...

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