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The Equation of the Line That Is Tangent to the Curve

Question 99

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The equation of the line that is tangent to the curve f(x)=(3x57x2+5)(x3+x1)f ( x ) = \left( 3 x ^ { 5 } - 7 x ^ { 2 } + 5 \right) \left( x ^ { 3 } + x - 1 \right) at the point (0, -5) is y = 5x - 5.

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