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An Appliance Store Manager Estimates That for X Television Ads R(x)=0.01x3+x23x+200R ( x ) = - 0.01 x ^ { 3 } + x ^ { 2 } - 3 x + 200

Question 47

Multiple Choice

An appliance store manager estimates that for x television ads run per day, R(x) =0.01x3+x23x+200R ( x ) = - 0.01 x ^ { 3 } + x ^ { 2 } - 3 x + 200 refrigerators will be sold per month. Find R(4) R ^ { \prime } ( 4 ) and interpret what it tells us about sales.


A) R(4) =4.52R ^ { \prime } ( 4 ) = 4.52 sales will be increasing at about 5 refrigerators per month per ad when they're running 4 ads.
B) R(4) =203.36R ^ { \prime } ( 4 ) = 203.36 the cost of refrigerators will be rising by $203.36 if they're selling 4 per day.
C) R(4) =4.52R ^ { \prime } ( 4 ) = 4.52 \text {; } they'll sell about 5 refrigerators if they run 4 ads per day.
D) R(4) =203.36R ^ { \prime } ( 4 ) = 203.36 \text {; } they'll sell about 203 refrigerators if they run 4 ads per day.

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