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The Equation of the Tangent Line to the Curve f(x)=(2x56x2+6)(x3+x1)f ( x ) = \left( 2 x ^ { 5 } - 6 x ^ { 2 } + 6 \right) \left( x ^ { 3 } + x - 1 \right)

Question 98

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The equation of the tangent line to the curve f(x)=(2x56x2+6)(x3+x1)f ( x ) = \left( 2 x ^ { 5 } - 6 x ^ { 2 } + 6 \right) \left( x ^ { 3 } + x - 1 \right) at the point (0, -6) is y = 6x - 6.

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