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The Maxwell-Ampere Law Can Be Written As; Bds=μ0I+μ0ε0dΦEdt\oint \vec { B } \cdot d \vec { s } = \mu _ { 0 } I + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }

Question 16

Multiple Choice

The Maxwell-Ampere Law can be written as; Bds=μ0I+μ0ε0dΦEdt\oint \vec { B } \cdot d \vec { s } = \mu _ { 0 } I + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t } . The term in the equation that relates to the magnetic field produced by an electric current is


A) Bds\oint \vec { B } \cdot d \vec { s }
B) μ0I\mu _ { 0 } I
C) μ0ε0dΦEdt\mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }
D) No term in this equation is related to the displacement current.

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