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Find a Function with the Given Partial Derivatives fx=2xy3\frac { \partial f } { \partial x } = 2 x y ^ { 3 }

Question 56

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Find a function with the given partial derivatives fx=2xy3\frac { \partial f } { \partial x } = 2 x y ^ { 3 } and fy=3x2y2\frac { \partial f } { \partial y } = 3 x ^ { 2 } y ^ { 2 }

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