If $\int _ { - 1 } ^ { 4 } f ( x ) d x = 3$

Short Answer

If $\int _ { - 1 } ^ { 4 } f ( x ) d x = 3$ , $\int _ { - 3 } ^ { 4 } f ( x ) d x = 6$ , $\int _ { - 1 }^4 g ( x ) d x = - 2$ and $\int _ { 4 } ^ { 6 } g ( x ) d x = 5$ , find the following, if possible.
(a) $\int _ { 4 } ^ { - 1 } 3 f ( x ) d x$ (b) $\int _ { - 3 } ^ { 4 } ( f ( x ) ) ^ { 2 } d x$ (c) $\int _ { 4 } ^ { 6 } ( 3 g ( x ) - x ) d x$