Given $\lim _ { x \rightarrow 2 } ( x + 3 ) = 5$

Multiple Choice

Given $\lim _ { x \rightarrow 2 } ( x + 3 ) = 5$ find a $\delta > 0$ in terms of an $\varepsilon > 0$ so that if $0 < | x - c | < \delta$ then $| f ( x ) - L | < \varepsilon$

A) ?/2
B) ?/3
C) ?
D) None of these.