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Find the Equation of a Linear Function Whose Graph Is x2y+2=0x - 2 y + 2 = 0

Question 78

Multiple Choice

Find the equation of a linear function whose graph is perpendicular to x2y+2=0x - 2 y + 2 = 0 and passes through the point (1, 3) .


A) y=2x5y = - 2 x - 5
B) y=2x+1y = - 2 x + 1
C) y=2x+5y = - 2 x + 5
D) y=2x5y = 2 x - 5

Correct Answer:

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