Data Set 9-3: N = 8 $\Sigma$ X = 48 $\Sigma$ X² = 351
-The T Value You Calculated When the \Sigma

Multiple Choice

Data Set 9-3: N = 8 $\Sigma$ X = 48 $\Sigma$ X² = 351
-The t value you calculated when the scores in Data Set 9-3 were tested against H₀: $\mu$ = 2.00 leads to the conclusion that the null hypothesis should be

A) rejected at the .05 level for a two-tailed test
B) rejected at the .05 and .01 level for a two-tailed test
C) rejected at the .05, .01, and .001 level for a two-tailed test
D) retained.