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    Chemistry
  3. Study Set
    Chemistry The Molecular Nature of Matter
  4. Exam
    Exam 18: Solubility and Simultaneous Equilibria
  5. Question
    For the H<sub>2</sub>CO<sub>3</sub>/ HCO<sub>3</sub>/CO<sub>3</sub><sup>2-</Sup> System at Room Temperature K<sub>a1</sub> =
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For the H2CO3/ HCO3/CO32- System at Room Temperature Ka1 =

Question 13

Question 13

Short Answer

For the H2CO3/ HCO3/CO32- system at room temperature Ka1 = 4.5 × 10-7, whileKa2 = 4.7 × 10-11. The Ksp for BaCO3 is 5.0 × 10-9.Calculate the equilibrium constant for the reaction,BaCO3(s)+ H+(aq) For the H<sub>2</sub>CO<sub>3</sub>/ HCO<sub>3</sub>/CO<sub>3</sub><sup>2-</sup> system at room temperature K<sub>a1</sub> = 4.5 × 10<sup>-</sup><sup>7</sup>, whileK<sub>a2</sub> = 4.7 × 10<sup>-11</sup>. The K<sub>sp</sub> for BaCO<sub>3</sub> is 5.0 × 10<sup>-9</sup>.Calculate the equilibrium constant for the reaction,BaCO<sub>3</sub>(s)+ H<sup>+</sup>(aq)   Ba<sup>2+</sup>(aq)+ HCO<sub>3</sub><sup>-</sup>(aq) Ba2+(aq)+ HCO3-(aq)

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