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Silver Bromide, AgBr, Is More Soluble in Ammonia Solution Than

Question 118

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Silver bromide, AgBr, is more soluble in ammonia solution than in pure water. The reaction is, AgBr(s) + 2 NH3(aq) Silver bromide, AgBr, is more soluble in ammonia solution than in pure water. The reaction is, AgBr(s) + 2 NH<sub>3</sub>(aq)    Ag(NH<sub>3</sub>) <sub>2</sub><sup>+</sup> + Br<sup>-</sup>(aq) Using K<sub>sp</sub>(AgBr) = 5.0 × 10<sup>-13</sup> and K<sub>form</sub> (Ag(NH<sub>3</sub>) <sub>2</sub><sup>+</sup>) = 1.60 × 10<sup>7</sup>, calculate the solubility of AgBr in 0.800 M ammonia solution..Hint: Combine the formation and solubility reactions to find the overall reaction and its equilibrium constant, and make sure to account for the presence of a common ion. A) 1.6 × 10<sup>-3</sup> M B) 2.3 × 10<sup>-3</sup> M C) 2.8 × 10<sup>-3</sup> M D) 4.2 × 10<sup>-3</sup> M E) 6.1 × 10<sup>-2</sup> M Ag(NH3) 2+ + Br-(aq) Using Ksp(AgBr) = 5.0 × 10-13 and Kform (Ag(NH3) 2+) = 1.60 × 107, calculate the solubility of AgBr in 0.800 M ammonia solution..Hint: Combine the formation and solubility reactions to find the overall reaction and its equilibrium constant, and make sure to account for the presence of a common ion.


A) 1.6 × 10-3 M
B) 2.3 × 10-3 M
C) 2.8 × 10-3 M
D) 4.2 × 10-3 M
E) 6.1 × 10-2 M

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