Solved

A Real World Application of Solubility Products Is Found in Softening

Question 24

Short Answer

A real world application of solubility products is found in softening "hard water" by removing calcium and magnesium ions present as the sulphate and carbonate salts. We can decrease the amount of Ca2+ in solution by addition of sodium carbonate, a strong electrolyte:Na2CO3 (s) \rightarrow 2 Na+ (aq) + CO32- (aq)By increasing the concentration of carbonate, we tend to drive the solubility equilibrium toward the reactant:CaCO3 (s)  A real world application of solubility products is found in softening  hard water  by removing calcium and magnesium ions present as the sulphate and carbonate salts. We can decrease the amount of Ca<sup>2+</sup> in solution by addition of sodium carbonate, a strong electrolyte:Na<sub>2</sub>CO<sub>3</sub> (s) \rightarrow 2 Na<sup>+ </sup>(aq)<sup> </sup>+ CO<sub>3</sub><sup>2-</sup> (aq)By increasing the concentration of carbonate, we tend to drive the solubility equilibrium toward the reactant:CaCO<sub>3</sub> <sub>(</sub><sub>s</sub><sub>)</sub>   Ca<sup>2+</sup> <sub>(</sub>aq<sub>)</sub> + CO<sub>3</sub><sup>2-</sup> (aq) K<sub>sp</sub> = 4.7 x 10<sup>-9</sup>If the initial [Ca<sup>2+</sup>] = 5.0 x 10<sup>-3</sup><sup> </sup>M, what percent of the [Ca<sup>2+</sup>] will be removed if the carbonate concentration is maintained at 1.0 x 10<sup>-3</sup> M? Ca2+ (aq) + CO32- (aq) Ksp = 4.7 x 10-9If the initial [Ca2+] = 5.0 x 10-3 M, what percent of the [Ca2+] will be removed if the carbonate concentration is maintained at 1.0 x 10-3 M?

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions