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    Mathematics
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    Calculus A Complete Course
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    Exam 15: Multiple Integration
  5. Question
    Find the Surface Area of the Part of the Parabolic
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Find the Surface Area of the Part of the Parabolic

Question 67

Question 67

Multiple Choice

Find the surface area of the part of the parabolic cylinder z = 1 - y2 that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane.


A) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units ( Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units - 1) square units
B) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units (5 Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units - 1) square units
C) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units ( Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units - 1) square units
D) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units (5 Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units - 1) square units
E) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units ( Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0)  in the xy-plane. A)    (   - 1)  square units B)    (5   - 1)  square units C)    (   - 1)  square units D)    (5   - 1)  square units E)    (   + 1)  square units + 1) square units

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