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    Calculus A Complete Course
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    Exam 13: Partial Differentiation
  5. Question
    The Equation X + Y<sup>2</sup> + Sin(xy) = 1 Defines
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The Equation X + Y2 + Sin(xy) = 1 Defines

Question 80

Question 80

Multiple Choice

The equation x + y2 + sin(xy) = 1 defines y as a function of x near the point (0, 1) . Find the value of The equation x + y<sup>2</sup> + sin(xy)  = 1 defines y as a function of x near the point (0, 1) . Find the value of   at that point. A)  -2 B)  -1 C)  1 D)  2 E)  0 at that point.


A) -2
B) -1
C) 1
D) 2
E) 0

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