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Find the Cartesian Equation of the Straight Line Tangent to the Plane

Question 112

Multiple Choice

Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t) = Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t)  =   + 2t + 2, y(t)  = 1 - 3   - 2   at the point on the curve where t = -1. A)  x -3y -1 = 0 B)  y =1 C)  y = x + 1 D)  3x -y -3 = 0 E)  y = 3x -7 + 2t + 2, y(t) = 1 - 3 Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t)  =   + 2t + 2, y(t)  = 1 - 3   - 2   at the point on the curve where t = -1. A)  x -3y -1 = 0 B)  y =1 C)  y = x + 1 D)  3x -y -3 = 0 E)  y = 3x -7 - 2 Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t)  =   + 2t + 2, y(t)  = 1 - 3   - 2   at the point on the curve where t = -1. A)  x -3y -1 = 0 B)  y =1 C)  y = x + 1 D)  3x -y -3 = 0 E)  y = 3x -7 at the point on the curve where t = -1.


A) x -3y -1 = 0
B) y =1
C) y = x + 1
D) 3x -y -3 = 0
E) y = 3x -7

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