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A Ball of Radius R Has Volume V(r) = $\pi$ Cubic Units

Question 18

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A ball of radius r has volume V(r) = $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ $\pi$ $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 $\le$ x $\le$ r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r.

A) S(r) = 4 $\pi$ $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ square units
B) S(r) = 8 $\pi$ $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ square units
C) S(r) = 2 $\pi$ $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ square units
D) S(r) = 8 $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ square units
E) S(r) = $\pi$ $A ball of radius r has volume V(r) = \pi cubic units. This volume can be regarded as a sum of volumes of concentric spherical shells having radii x units (where 0 \le x \le r) and thickness dx. Use this fact to find the surface area S(r) of a sphere of radius r. A) S(r) = 4 \pi square units B) S(r) = 8 \pi square units C) S(r) = 2 \pi square units D) S(r) = 8 square units E) S(r) = \pi square units$ square units

A Ball of Radius R Has Volume V(r) = π\piπ Cubic Units

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A Ball of Radius R Has Volume V(r) = $\pi$ Cubic Units

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