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The Figure Shows Two Forces Acting on an Object

Question 11

Multiple Choice

The figure shows two forces acting on an object. They have magnitudes F1 = 6.3 N and
F2 = 2.1 N. What third force will cause the object to be in equilibrium?
The figure shows two forces acting on an object. They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N. What third force will cause the object to be in equilibrium? A) 6.6 N at 162° counterclockwise from B) 6.6 N at 108° counterclockwise from C) 4.2 N at 162° counterclockwise from D) 4.2 N at 108° counterclockwise from


A) 6.6 N at 162° counterclockwise from The figure shows two forces acting on an object. They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N. What third force will cause the object to be in equilibrium? A) 6.6 N at 162° counterclockwise from B) 6.6 N at 108° counterclockwise from C) 4.2 N at 162° counterclockwise from D) 4.2 N at 108° counterclockwise from
B) 6.6 N at 108° counterclockwise from The figure shows two forces acting on an object. They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N. What third force will cause the object to be in equilibrium? A) 6.6 N at 162° counterclockwise from B) 6.6 N at 108° counterclockwise from C) 4.2 N at 162° counterclockwise from D) 4.2 N at 108° counterclockwise from
C) 4.2 N at 162° counterclockwise from The figure shows two forces acting on an object. They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N. What third force will cause the object to be in equilibrium? A) 6.6 N at 162° counterclockwise from B) 6.6 N at 108° counterclockwise from C) 4.2 N at 162° counterclockwise from D) 4.2 N at 108° counterclockwise from
D) 4.2 N at 108° counterclockwise from The figure shows two forces acting on an object. They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N. What third force will cause the object to be in equilibrium? A) 6.6 N at 162° counterclockwise from B) 6.6 N at 108° counterclockwise from C) 4.2 N at 162° counterclockwise from D) 4.2 N at 108° counterclockwise from

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