The Volume of Pollutants (In Millions of Cubic Feet) in a Certain

Short Answer

The volume of pollutants (in millions of cubic feet) in a certain reservoir is given by P(t)=300 + 30t , where t is time in years. The volume of the reservoir (including pollutants) is gradually increasing and is given by ^{R(t) = 14,000+ 130t} . Let ^C(t) be the fraction of the reservoir's volume that consists of pollutants. What percent of the reservoir's total volume consisted of pollutants in the year t = 0? Round to 1 decimal place.