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Consider a Block (8x8 Pixels) of an Image as Shown 8×88 \times 8

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Consider a block (8x8 pixels) of an image as shown below. In a particular color plane, the pixel values are as follows:
 Consider a block (8x8 pixels) of an image as shown below. In a particular color plane, the pixel values are as follows:     A standard 2-D DCT for an  8 \times 8  block size is defined as  F(u, v)=\frac{C(u) C(v)}{4} \sum_{i=0}^{7} \sum_{j=0}^{7} \cos \frac{(2 i+1) \cdot u \pi}{16} \cos \frac{(2 j+1) \cdot v \pi}{16} f(i, j),   where  i, j, u, v  are in  0 . .7 , and the constants  C(u)  and  C(v)  are determined by  C(\xi)=\left\{\begin{array}{cl} \frac{\sqrt{2}}{2} & \text { if } \xi=0 \\ 1 & \text { otherwise. } \end{array}\right.  Suppose we compute a DCT  F(u, v) , where  u  is rows and  v  is columns. (a) What value does  F(0,0)  have? Explain. (b) Describe the contents (roughly) of the other components. Explain. Hint: Just thinking about it, rather than calculating everything, will save you time. What are values  F(u, 0) . What are values  F(0, v) .  What are other values  F(u, v) .
A standard 2-D DCT for an 8×88 \times 8 block size is defined as
F(u,v)=C(u)C(v)4i=07j=07cos(2i+1)uπ16cos(2j+1)vπ16f(i,j),F(u, v)=\frac{C(u) C(v)}{4} \sum_{i=0}^{7} \sum_{j=0}^{7} \cos \frac{(2 i+1) \cdot u \pi}{16} \cos \frac{(2 j+1) \cdot v \pi}{16} f(i, j),
where i,j,u,vi, j, u, v are in 0..70 . .7 , and the constants C(u)C(u) and C(v)C(v) are determined by
C(ξ)={22 if ξ=01 otherwise. C(\xi)=\left\{\begin{array}{cl}\frac{\sqrt{2}}{2} & \text { if } \xi=0 \\1 & \text { otherwise. }\end{array}\right.
Suppose we compute a DCT F(u,v)F(u, v) , where uu is rows and vv is columns.
(a) What value does F(0,0)F(0,0) have? Explain.
(b) Describe the contents (roughly) of the other components. Explain.
Hint: Just thinking about it, rather than calculating everything, will save you time. What are values F(u,0)F(u, 0) . What are values F(0,v)F(0, v) .
What are other values F(u,v)F(u, v) .

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If we apply DCT on this block then blured image, sin...

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