Short Answer
How much heat would be required to melt 1.0 kg of LEAD, initially at room temperature? Assume room temperature to be 20° C.
(c = 920 J/kg-C°
Lf = 0.25 × 105 J/kg
LV = 8.67 × 105 J/kg
melts at 328.°C
boils at 1744.°C)
Correct Answer:
Verified
Correct Answer:
Verified
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