The Mean Free Path of a Molecule Is $2.25 \times 10^{-7} \mathrm{~m}$

Multiple Choice

The mean free path of a molecule is $2.25 \times 10^{-7} \mathrm{~m}$ in an ideal gas at standard temperature and pressure $\left(0^{\circ} \mathrm{C}\right.$ and $1 \mathrm{~atm})$ . What is the mean free path if the diameter of the molecule is doubled?

A) $0.56 \times 10^{-7} \mathrm{~m}$
B) $0.45 \times 10^{-7} \mathrm{~m}$
C) $0.75 \times 10^{-7} \mathrm{~m}$
D) $1.13 \times 10^{-7} \mathrm{~m}$
E) $0.23 \times 10^{-7} \mathrm{~m}$