The Mean Free Path of a Molecule Is $2.25 \times 10^{-7} \mathrm{~m}$

Multiple Choice

The mean free path of a molecule is $2.25 \times 10^{-7} \mathrm{~m}$ in an ideal gas at standard temperature and pressure $\left(0^{\circ} \mathrm{C}\right.$ and $1 \mathrm{~atm}$ ) . What is the mean free path if the diameter of the molecule and the temperature of the gas are both doubled?

A) $1.13 \times 10^{-7} \mathrm{~m}$
B) $2.25 \times 10^{-7} \mathrm{~m}$
C) $3.00 \times 10^{-7} \mathrm{~m}$
D) $3.75 \times 10^{-7} \mathrm{~m}$
E) $0.75 \times 10^{-7} \mathrm{~m}$