The Mean Free Path of a Molecule Is $2.25 \times 10^{-7} \mathrm{~m}$

Multiple Choice

The mean free path of a molecule is $2.25 \times 10^{-7} \mathrm{~m}$ in an ideal gas at standard temperature and pressure $\left(0^{\circ} \mathrm{C}\right.$ and $1 \mathrm{~atm})$ . What is the mean free path if the pressure of the gas is doubled but the temperature is constant?

A) $2.25 \times 10^{-7} \mathrm{~m}$
B) $3.38 \times 10^{-7} \mathrm{~m}$
C) $1.13 \times 10^{-7} \mathrm{~m}$
D) $0.75 \times 10^{-7} \mathrm{~m}$
E) $3.75 \times 10^{-7} \mathrm{~m}$