When light ray goes through two thick rectangular slabs of glass, each of the same uniform thickness. The first slab has index of refraction

\mathrm{n}_{1}

and the second

\mathrm{n}_{2}

. If

\mathrm{n}_{1}<\mathrm{n}_{2}

. How does the original angle of incidence

\theta_{\mathrm{i}}

into the first slab compare to the final angle of refraction

\theta_{\mathrm{f}}

where the ray leaves the second slab going back into air?
$When light ray goes through two thick rectangular slabs of glass, each of the same uniform thickness. The first slab has index of refraction \mathrm{n}_{1} and the second \mathrm{n}_{2} . If \mathrm{n}_{1}<\mathrm{n}_{2} . How does the original angle of incidence \theta_{\mathrm{i}} into the first slab compare to the final angle of refraction \theta_{\mathrm{f}} where the ray leaves the second slab going back into air? A) \theta_{\mathrm{i}}=\left(\mathrm{n}_{1} / \mathrm{n}_{2}\right) \theta_{\mathrm{f}} B) \theta_{\mathrm{i}}<\theta_{\mathrm{f}} C) \theta_{\mathrm{i}}>\theta_{\mathrm{f}} D) \theta_{\mathrm{i}}=\theta_{\mathrm{f}} E) more information is needed$
A)

\theta_{\mathrm{i}}=\left(\mathrm{n}_{1} / \mathrm{n}_{2}\right) \theta_{\mathrm{f}}

\theta_{\mathrm{i}}<\theta_{\mathrm{f}}

\theta_{\mathrm{i}}>\theta_{\mathrm{f}}

\theta_{\mathrm{i}}=\theta_{\mathrm{f}}

E) more information is needed

An Optical Fiber Having Index of Refraction 1 41.8∘41.8^{\circ}41.8∘ B) 63.2∘63.2^{\circ}63.2∘ C) 26.8∘26.8^{\circ}26.8∘

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An Optical Fiber Having Index of Refraction 1 $41.8^{\circ}$ B) $63.2^{\circ}$ C) $26.8^{\circ}$

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