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    Mathematics
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    A Graphical Approach to Precalculus with Limits
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    Exam 5: Inverse, Exponential, and Logarithmic Functions
  5. Question
    Solve the Equation\(9^{x+3}=\left(\frac{1}{3}\right)^{x-7}\) Analytically
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Solve the Equation 9x+3=(13)x−79^{x+3}=\left(\frac{1}{3}\right)^{x-7}9x+3=(31​)x−7 Analytically

Question 18

Question 18

Short Answer

Solve the equation 9x+3=(13)x−79^{x+3}=\left(\frac{1}{3}\right)^{x-7}9x+3=(31​)x−7 analytically.

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