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Consider the Equation log6x+log6(x5)=1\log _{6} x+\log _{6}(x-5)=1
(A) Solve the Equation Analytically

Question 5

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Consider the equation log6x+log6(x5)=1\log _{6} x+\log _{6}(x-5)=1 .
(a) Solve the equation analytically. If there is an extraneous value, what is it?
(b) To support the solution in part (a), we may graph y1=log6x+log6(x5)1y_{1}=\log _{6} x+\log _{6}(x-5)-1 and find the xx -intercept.
Write an expression for y1y_{1} using the change-of-base rule with base 10, and graph the function to support the solution from part (a).
(c) Use the graph to solve the inequality log6x+log6(x5)<1\log _{6} x+\log _{6}(x-5)<1 .

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