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    A Graphical Approach to Precalculus with Limits
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    Exam 5: Inverse, Exponential, and Logarithmic Functions
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    Solve the Equation\(\left(\frac{1}{36}\right)^{2 x-3}=6^{3 x+1}\) Analytically
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Solve the Equation (136)2x−3=63x+1\left(\frac{1}{36}\right)^{2 x-3}=6^{3 x+1}(361​)2x−3=63x+1 Analytically

Question 65

Question 65

Short Answer

Solve the equation (136)2x−3=63x+1\left(\frac{1}{36}\right)^{2 x-3}=6^{3 x+1}(361​)2x−3=63x+1 analytically.

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