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    A Graphical Approach to Precalculus with Limits
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    Exam 5: Inverse, Exponential, and Logarithmic Functions
  5. Question
    Solve the Equation\(25^{x-9}=\left(\frac{1}{125}\right)^{2 x-2}\) Analytically
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Solve the Equation 25x−9=(1125)2x−225^{x-9}=\left(\frac{1}{125}\right)^{2 x-2}25x−9=(1251​)2x−2 Analytically

Question 58

Question 58

Short Answer

Solve the equation 25x−9=(1125)2x−225^{x-9}=\left(\frac{1}{125}\right)^{2 x-2}25x−9=(1251​)2x−2 analytically.

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