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Consider the Boundary Value Problem
- = F(x), 0 $y(x)=\int_{0}^{1}-G(-x, s) f(s) d s$

Question 3

Multiple Choice

Consider the boundary value problem
- $Consider the boundary value problem - = f(x) , 0 < x < 1, y(0) = 0, (1) = 0 Which of these is the Green's function representation of the solution of the given boundary value problem? A) y(x) =\int_{0}^{1}-G(-x, s) f(s) d s B) y(x) =\int_{0}^{1}-G(x, s) f(s) d s C) y(x) =\int_{0}^{1} G(-x, s) f(s) d s D) y(x) =\int_{0}^{1} G(x, s) f(s) d s$ = f(x) , 0 < x < 1, y(0) = 0, $Consider the boundary value problem - = f(x) , 0 < x < 1, y(0) = 0, (1) = 0 Which of these is the Green's function representation of the solution of the given boundary value problem? A) y(x) =\int_{0}^{1}-G(-x, s) f(s) d s B) y(x) =\int_{0}^{1}-G(x, s) f(s) d s C) y(x) =\int_{0}^{1} G(-x, s) f(s) d s D) y(x) =\int_{0}^{1} G(x, s) f(s) d s$ (1) = 0
Which of these is the Green's function representation of the solution of the given boundary value problem?

A) $y(x) =\int_{0}^{1}-G(-x, s) f(s) d s$
B) $y(x) =\int_{0}^{1}-G(x, s) f(s) d s$
C) $y(x) =\int_{0}^{1} G(-x, s) f(s) d s$
D) $y(x) =\int_{0}^{1} G(x, s) f(s) d s$

Consider the Boundary Value Problem - = F(x), 0 y(x)=∫01−G(−x,s)f(s)ds y(x)=\int_{0}^{1}-G(-x, s) f(s) d s y(x)=∫01​−G(−x,s)f(s)ds

Multiple Choice

Correct Answer:VerifiedShow Answer

Consider the Boundary Value Problem
- = F(x), 0 $y(x)=\int_{0}^{1}-G(-x, s) f(s) d s$

Correct Answer:
Verified