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What Is the Steady State Solution for the Heat Conduction v(x)=140x+201 v(x)=\frac{1}{40} x+201

Question 18

Multiple Choice

What is the steady state solution for the heat conduction equation
 What is the steady state solution for the heat conduction equation   Equipped with the following boundary conditions: U(0, t)  - (0, t)  = 5 U(40, t)  + (40, t)  = 4 A)    v(x) =\frac{1}{40} x+201   B)    v(x) =\frac{1}{40} x+\frac{201}{40}   C)    v(x) =-\frac{1}{40} x+199   D)    v(x) =-\frac{1}{40} x+\frac{199}{40}
Equipped with the following boundary conditions:
U(0, t) - (0, t) = 5
U(40, t) + (40, t) = 4


A) v(x) =140x+201 v(x) =\frac{1}{40} x+201
B) v(x) =140x+20140 v(x) =\frac{1}{40} x+\frac{201}{40}
C) v(x) =140x+199 v(x) =-\frac{1}{40} x+199
D) v(x) =140x+19940 v(x) =-\frac{1}{40} x+\frac{199}{40}

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