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Consider the Initial Value Problem This Question Relates to Using

Question 17

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Consider the initial value problem  Consider the initial value problem   This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =   Which of the following equals    A)    y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    B)    y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    C)    y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)    D)    y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)  This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =  Consider the initial value problem   This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =   Which of the following equals    A)    y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    B)    y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    C)    y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)    D)    y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)  Which of the following equals  Consider the initial value problem   This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =   Which of the following equals    A)    y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    B)    y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    C)    y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)    D)    y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)


A) y2=1200(92002112002) y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)
B) y2=(92002112002) y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)
C) y2=11200+(920022112002) y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)
D) y2=11200+1200(92002112002) y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)

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