Consider the initial value problem $Consider the initial value problem This question is related to using the predictor-corrector method to estimate the solution y(0.2) using a step size of h = 0.05. For this problem, you will need these values to carry out the computations: Which of the following is the predicted value for A) y_{3}+\frac{0.05}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right] B) y_{3}+\frac{0.05}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right] C) y_{3}+\frac{1}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right] D) y_{3}+\frac{1}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right]$ This question is related to using the predictor-corrector method to estimate the solution y(0.2) using a step size of h = 0.05.
For this problem, you will need these values to carry out the computations:
$Consider the initial value problem This question is related to using the predictor-corrector method to estimate the solution y(0.2) using a step size of h = 0.05. For this problem, you will need these values to carry out the computations: Which of the following is the predicted value for A) y_{3}+\frac{0.05}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right] B) y_{3}+\frac{0.05}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right] C) y_{3}+\frac{1}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right] D) y_{3}+\frac{1}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right]$
Which of the following is the predicted value for $Consider the initial value problem This question is related to using the predictor-corrector method to estimate the solution y(0.2) using a step size of h = 0.05. For this problem, you will need these values to carry out the computations: Which of the following is the predicted value for A) y_{3}+\frac{0.05}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right] B) y_{3}+\frac{0.05}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right] C) y_{3}+\frac{1}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right] D) y_{3}+\frac{1}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right]$
A)

y_{3}+\frac{0.05}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right]

y_{3}+\frac{0.05}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right]

y_{3}+\frac{1}{24}\left[59\left(-3 \times 0.15+7 y_{3}\right)-55\left(-3 \times 0.10+7 y_{2}\right)-37\left(-3 \times 0.05+7 y_{1}\right)+9 \times 5\right]

y_{3}+\frac{1}{24}\left[55\left(-3 \times 0.15+7 y_{3}\right)-59\left(-3 \times 0.10+7 y_{2}\right)+37\left(-3 \times 0.05+7 y_{1}\right)-9 \times 5\right]

For the Following Differential Equation, Use the Fourth-Order Adams-Moulton Formula

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