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Find the General Solution of the Cauchy Euler Differential Equation $y=C_{1}(x-3)^{5}+C_{2}(x-3)^{5} \ln x$

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Find the general solution of the Cauchy Euler differential equation $Find the general solution of the Cauchy Euler differential equation . A) y=C_{1}(x-3) ^{5}+C_{2}(x-3) ^{5} \ln x B) y=C_{1}(x-3) ^{-5}+C_{2}(x-3) ^{5} C) y=C_{1}(x-3) ^{-5}+C_{2}(x-3) ^{-5} \ln x D) y=C_{1}(x-3) ^{5}+C_{2}(x-3) ^{10}$ .

A) $y=C_{1}(x-3) ^{5}+C_{2}(x-3) ^{5} \ln x$
B) $y=C_{1}(x-3) ^{-5}+C_{2}(x-3) ^{5}$
C) $y=C_{1}(x-3) ^{-5}+C_{2}(x-3) ^{-5} \ln x$
D) $y=C_{1}(x-3) ^{5}+C_{2}(x-3) ^{10}$

Find the General Solution of the Cauchy Euler Differential Equation y=C1(x−3)5+C2(x−3)5ln⁡x y=C_{1}(x-3)^{5}+C_{2}(x-3)^{5} \ln x y=C1​(x−3)5+C2​(x−3)5lnx

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Find the General Solution of the Cauchy Euler Differential Equation $y=C_{1}(x-3)^{5}+C_{2}(x-3)^{5} \ln x$

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